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Introduction to Linear Algebra

Session Preparation:

Brooks: Chapter 7

Some of the exercises may require you to use Python. You may also need to install the numpy and sympy libraries if you haven't already.

Resources Danish Class:

Session notes

Session Resources

Exercises

Exercise 1: Echelon and Reduced Echelon Form

Determine whether the following matrices are in reduced echelon form, echelon form, or neither.

a. \(\begin{bmatrix} 1 & 0 & 2 & 1\\ 0 & 1 & -3 & 0\end{bmatrix}\)

b. \(\begin{bmatrix} 1 & 2 & -2 & 5\\ 0 & 1 & 0 & -1\\ 0 & 0 & 1 & 3 \\ 0 & 0 & 0 & 1\end{bmatrix}\)

c. \(\begin{bmatrix} -1 & 0\\ 0 & 4\\ 0 & 0 \end{bmatrix}\)

d. \(\begin{bmatrix} 1 & 0 & 1 & 0 & -1\\ 0 & 1 & 1 & 0 & 0\\ 0 & 0 & 0 & 0 & 0\\ 0 & 0 & 0 & 1 & -1\end{bmatrix}\)

e. \(\begin{bmatrix} 0 & 3 & 0 & 4\\ 0 & 0 & -2 & -2\\ 0 & 0 & 0 & 7\end{bmatrix}\)

f. \(\begin{bmatrix} 1 & 0 & 0 & 1\\ 0 & 0 & 1 & -2\\ 0 & 0 & 0 & 1\end{bmatrix}\)

 

a. reduced echelon form

b. echelon form

c. echelon form

d. neither

e. echelon form

f. echelon form

Exercise 2: Row operations

Explain which row operations are used in the calculations below.

a. \(\begin{bmatrix} 4 & -3 & 1 & 2 \\ 3 & 1 & -5 & 6 \\ 1 & 1 & 2 & 4 \\ \end{bmatrix} \sim \begin{bmatrix} 1 & 1 & 2 & 4 \\ 3 & 1 & -5 & 6 \\ 4 & -3 & 1 & 2 \\ \end{bmatrix}\)

 

Swap: \(r_1 \leftrightarrow r_3\)

b. \(\begin{bmatrix} 1 & 1 & 2 & 4 \\ 3 & 1 & -5 & 6 \\ 4 & -3 & 1 & 2 \\ \end{bmatrix} \sim \begin{bmatrix} 1 & 1 & 2 & 4 \\ 0 & -2 & -11 & -6 \\ 4 & -3 & 1 & 2 \\ \end{bmatrix}\)

 

Replacement: \(r_2 \rightarrow r_2 - 3r_1\)

c. \(\begin{bmatrix} 1 & 1 & 2 & 4 \\ 0 & -2 & -11 & -6 \\ 4 & -3 & 1 & 2 \\ \end{bmatrix} \sim \begin{bmatrix} 1 & 1 & 2 & 4 \\ 0 & -2 & -11 & -6 \\ 0 & -7 & -7 & -14 \\ \end{bmatrix}\)

 

Replacement: \(r_3 \rightarrow r_3 - 4r_1\)

d. \(\begin{bmatrix} 1 & 1 & 2 & 4 \\ 0 & -2 & -11 & -6 \\ 0 & -7 & -7 & -14 \\ \end{bmatrix} \sim \begin{bmatrix} 1 & 1 & 2 & 4 \\ 0 & -2 & -11 & -6 \\ 0 & 1 & 1 & 2 \\ \end{bmatrix}\)

 

Scaling: \(r_3 \rightarrow -\frac{1}{7}r_3\)

e. \(\begin{bmatrix} 1 & 1 & 2 & 4 \\ 0 & -2 & -11 & -6 \\ 0 & 1 & 1 & 2 \\ \end{bmatrix} \sim \begin{bmatrix} 1 & 1 & 2 & 4 \\ 0 & 1 & 1 & 2 \\ 0 & -2 & -11 & -6 \\ \end{bmatrix}\)

 

Swap: \(r_2 \leftrightarrow r_3\)

f. \(\begin{bmatrix} 1 & 1 & 2 & 4 \\ 0 & 1 & 1 & 2 \\ 0 & -2 & -11 & -6 \\ \end{bmatrix} \sim \begin{bmatrix} 1 & 1 & 2 & 4 \\ 0 & 1 & 1 & 2 \\ 0 & 0 & -9 & -2 \\ \end{bmatrix}\)

 

Replacement: \(r_3 \rightarrow r_3 + 2r_2\)

g. The reduced matrix from (f) is the augmented matrix for a system of linear equations. Does this system have no solution, a unique solution, or infinitely many solutions?

 

The system has a unique solution, since there is a pivot in each column of the coefficient part of the reduced matrix.

Exercise 3: System of linear equations

Given the following system of linear equations:

\[ \begin{aligned} 2x_1 - 4x_2 + 6x_3 &= 2 \\ x_1 + x_3 &= 3 \\ -4x_1 + 2x_2 &= 2 \end{aligned} \]

a. Write down the augmented matrix for the system.

 

\(\begin{bmatrix} 2 & -4 & 6 & 2\\ 1 & 0 & 1 & 3\\ -4& 2 & 0 & 2 \end{bmatrix}\)

b. Use row operations to get the reduced row echelon form of the matrix and write down the solution.

 

RREF: \(\begin{bmatrix} 1 & 0 & 0 & 1\\ 0 & 1 & 0 & 3\\ 0 & 0 & 1 & 2 \end{bmatrix}\)

Solution: \(\begin{cases} x_1 = 1\\ x_2 = 3\\ x_3 = 2 \end{cases}\)

Exercise 4: Row Reduction

Solve the systems whose augmented matrices are given below. Write down the general solution, i.e. write the basic variables in terms of the free variables.

a. \(\begin{bmatrix} 1 & 2 & 3 & 4\\ 4 & 8 & 9 & 4\end{bmatrix}\)

 

\(\begin{cases} x_1 = -8-2x_2\\ x_2 \text{ free}\\ x_3 = 4 \end{cases}\)

b. \(\begin{bmatrix} 1 & -1 & -2 & 3\\ 4 & -2 & -8 & 2\end{bmatrix}\)

 

\(\begin{cases} x_1 = -2+2x_3\\ x_2 = -5\\ x_3 \text{ free} \end{cases}\)

c. \(\begin{bmatrix} -2 & 4 & -3 & 0\\ 4 & -8 & 6& 0\\ -6& 12& -9 & 0\end{bmatrix}\)

 

\(\begin{cases} x_1 = 2x_2 - \frac{3}{2}x_3\\ x_2 \text{ free}\\ x_3 \text{ free} \end{cases}\)

Exercise 5: Consistency of the system

Which of the augmented matrices below represent an inconsistent system of equations?

a. \(\begin{bmatrix} 0 & 3 & -2 & 1\\ 0 & 0 & -1 & 4\\ 0 & 0 & 0 & 0 \end{bmatrix}\)

b. \(\begin{bmatrix} -1 & 3 & 1 \\ 0 & 5 & 3 \\ 0 & 0 & 6 \end{bmatrix}\)

c. \(\begin{bmatrix} 7 & 1 & 1 \\ 0 & 2 & 2 \\ 0 & 0 & 3 \\ 0 & 0 & 0 \end{bmatrix}\)

d. \(\begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}\)

e. \(\begin{bmatrix} -3 & 0 & 0 & 9\\ 0 & 1 & 0 & 0\\ 0 & 0 & 4 & 0 \end{bmatrix}\)

f. \(\begin{bmatrix} 0 & 0 & 6 & 3 \end{bmatrix}\)

 

inconsistent: b, c, d

consistent: a, e, f

g. For the consistent systems find the general solution.

 

a. \(\begin{cases} x_1 \text{ free}\\ x_2 = -\frac{7}{3}\\ x_3 = -4 \end{cases}\)

e. \(\begin{cases} x_1 = - 3\\ x_2 = 0\\ x_3 = 0 \end{cases}\)

f. \(\begin{cases} x_1 \text{ free}\\ x_2 \text{ free}\\ x_3 = \frac{1}{2} \end{cases}\)

Exercise 6: Plan a diet

Use Python to solve this exercise.

For a week you decide to eat only butter, apples, and oats.

Nutritional values per 100 g Butter Apple Oats Rye bread
Protein (g) 0.2 0.3 14.0 6.4
Fat (g) 82.5 0.2 6.9 4.7
Carbohydrates (g) 0.0 12.1 57.0 32.0

a. How much butter, apple, and oats do you need to eat to get 50 g of protein, 70 g of fat, and 260 g of carbohydrates per day?

 

\(\begin{cases} 54.7 \text{ g butter}\\ 522.8\text{ g apple}\\ 345.2 \text{ g oats}\end{cases}\)

Next week, you decide to replace apples with rye bread.

b. Is it possible to plan a diet of butter, rye bread, and oats to still get 50 g of protein, 70 g of fat and 260 g of carbohydrate per day?

 

No, the system of linear equations has a unique solution. However, the solution contains a negative amount of oats, which does not make sense.